X Trench Run Math !!exclusive!! Here

[ P_\texthit = 1 - \exp\left( -\fracR^22\sigma^2 \right) ]

[ h = \frac12 a t^2 ] [ d = v t ]

[ P_\texthit \approx 1 - e^-0.913 \approx 1 - 0.401 \approx 0.599 \ (\text59.9%) ] x trench run math

[ a = \frac2(20)(100^2)10^2 = \frac40 \cdot 10,000100 = 4,000 \ \textm/s^2 \ (\approx 408g) ]

To hit a 2 m wide port from a horizontal offset of zero (directly above), the required vertical acceleration: [ P_\texthit = 1 - \exp\left( -\fracR^22\sigma^2 \right)

Plug numbers: (\fracR^22\sigma^2 = \frac12(0.74^2) = \frac11.095 \approx 0.913)

No lateral motion needed if flying straight down the trench centerline — but if the port is offset, or the X-wing is drifting: 000100 = 4

[ t = \fracL\textspeed = \frac60,000 \text m180 \text m/s \approx 333 \text seconds \ (\text5 min 33 sec) ]