Cs50 Tideman -

// Display after sorting with tie information printf("\n--- AFTER SORTING (by victory strength) ---\n"); for (int i = 0; i < pair_count; i++) { int margin = preferences[pairs[i].winner][pairs[i].loser] - preferences[pairs[i].loser][pairs[i].winner]; printf("\nRank %i: ", i + 1); if (margin > 0) printf("STRONGEST - "); else if (margin == 0) printf("TIE - "); display_pair_votes(i); }

if (margin > 0) printf(" Margin: %s wins by %i votes\n", candidates[pairs[pair_index].winner], margin); else if (margin < 0) printf(" Margin: %s wins by %i votes\n", candidates[pairs[pair_index].loser], -margin); else printf(" TIE! Both have equal votes\n"); } cs50 tideman

I'll help you create a feature for CS50's Tideman problem. Since you didn't specify which feature, I'll suggest that shows how ties are resolved in the Tideman algorithm. Feature: Tie-Breaking Visualization This feature adds a function that visualizes how the Tideman algorithm resolves tied preferences and locked pairs, making it easier to debug and understand the election process. Code Implementation // Add this function to your tideman.c file // Structure to track tie information typedef struct { int winner; int loser; int margin; // margin of victory (votes_winner - votes_loser) bool is_tie; // whether this pair is tied } pair_info; // Display after sorting with tie information printf("\n---

for (int i = 0; i < pair_count; i++) { int winner = pairs[i].winner; int loser = pairs[i].loser; printf("\nAttempting to lock: %s → %s", candidates[winner], candidates[loser]); // Check if adding this edge creates a cycle if (!creates_cycle(winner, loser)) { locked[winner][loser] = true; printf(" ✓ LOCKED\n"); // Visualize current state of locked pairs printf(" Current locked pairs: "); bool has_locked = false; for (int a = 0; a < candidate_count; a++) { for (int b = 0; b < candidate_count; b++) { if (locked[a][b]) { printf("%s→%s ", candidates[a], candidates[b]); has_locked = true; } } } if (!has_locked) printf("none"); printf("\n"); } else { printf(" ✗ SKIPPED (would create cycle)\n"); } } for (int i = 0